In engineering mechanics length, mass, time and force are the
basic units used therefore; the following are the units systems are adopted in
the engineering mechanics
1. International System of Units (SI):
In SI system of units the basic units are length, time, and mass
which are arbitrarily defined as the meter (m), second (s), and kilogram (kg).
Force is the derived unit.
1N = 1 kg. 1 m/s2
2. CGS systems of units
In CGS system of units, the basic units are length, time, and mass
which are arbitrarily defined as the centimetre (cm), second (s), and gram (g).
Force is the derived
Units 1 Dyne = 1 g. 1 cm/s2
3. British systems of units
In CGS system of units, the basic units are length, time, and mass
which are arbitrarily defined as the centimetre (cm), second (s), and gram (g).
Force is the derived Units
1 lb = 1lbg. 1ft/s2
4. U.S. Customary Units
The basic units are length, time, and force which are arbitrarily
defined as the foot (ft), second (s), and pound (lb). Mass is the derived unit,
Trigonometry
The measurement of the triangle sides and angles is called
trigonometry. Let us consider right-angled triangle ABC as shown in figure
Than the following ratio can be considered for both the triangles
Sin θ = per/hyp = a/b
Sin θ = per/hyp = c/b
Cos θ = base/hyp = c/b
Cos θ = base/hyp =a/b
Tan θ = per/base = a/c
Tan θ = per/base = c/a
The any side of the right angled triangle may be calculated by
b2 = a2 + b2
Similarly consider the following Triangle
The any side of the triangle can be calculated by using the cosine
law, let suppose
we have to calculate the side “AC” that is “b”
then
b2 = a2 + c2 – (2bc)cos γ
Similarly, to calculate sides “AB” that is “c”
and “AC” that is “a” then by using the
cosine law as below
c2 = a2 + b2 – 2abcos α
And a2
= c2 + b2 – 2cbcos β
The sides of the triangle ABC can be calculated by using the sin
law
Principle of transmissibility of forces
The state of rest of motion of a rigid body is unaltered if a
force acting in the body is replaced by another force of the same magnitude and
direction but acting anywhere on the body along the line of action of the
replaced force.
For example the force F acting on a rigid body
at point A. According to the principle of transmissibility of forces, this
force has the same effect on the body as a force F applied at point B.
The following two points should be considered while using this
principle.
1. In engineering mechanics we deal with only rigid bodies. If deformation
of the body is to be considered in a problem. The law of transmissibility of
forces will not hold good.
2. By transmission of the force only the state
of the body is unaltered, but not the internal stresses which may develop in
the body Therefore this law can be applied only to problems in which rigid
bodies are involved.
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